← Quantitative Aptitude

Coordinate Geometry — Questions with Solutions

1 solved Coordinate Geometry questions from Quantitative Aptitude, as asked in SSC CGL and other SSC exams. Read the answer and explanation below, then practise the full set in the practice section.

Practise this topic

Q1. If the equations $4x + (k - 2)y + 3 = 0$ and $(k - 2)x + 9y - 5 = 0$ (where $k > 0$) are parallel, then find the value of $k^2 + 6$.

यदि समीकरण $4x + (k - 2)y + 3 = 0$ और $(k - 2)x + 9y - 5 = 0$ ($k > 0$) समानांतर हैं, तो $k^2 + 6$ का मान ज्ञात कीजिए।

  1. A. $68$
  2. B. $70$
  3. C. $72$
  4. D. $64$

Solution

For parallel lines, $a_1/a_2 = b_1/b_2 \implies 4/(k-2) = (k-2)/9 \implies (k-2)^2 = 36 \implies k-2 = 6 \implies k = 8$. Then $k^2 + 6 = 64 + 6 = 70$.